Sketch the region common to the circle x^2 + y^2 = 16 and the parabola x^2 = 6y. Also, find the area of the region, using integration. - Sarthaks eConnect | Largest Online Education Community
Sketch the region common to the circle x^2 + y^2 = 16 and the parabola x^2 = 6y. Also, find the area of the region, using integration. - Sarthaks eConnect | Largest Online Education Community
SOLUTION: x^2+y^2=6y sketch the graph of the equation. This is one of the questions that are difficult for me
the equation of a chord of the circle x^2+y^2+4x 6y=0 is given by x+2y=0 . the equation of the circle described on this chord as diameter is
SOLUTION: he general form of the equation of a circle is x2+y2+2x− 6y+1=0. What are the coordinates of the center of the circle?
![SOLVED: following into polar equation: x2 +y2 6y = 0 Convert the r= 6cos8 0 ,2 6cos 0 r2 6sin Or = 6sin8 SOLVED: following into polar equation: x2 +y2 6y = 0 Convert the r= 6cos8 0 ,2 6cos 0 r2 6sin Or = 6sin8](https://cdn.numerade.com/ask_images/a8e1b2376b284bedbb4be5a829558aea.jpg)
SOLVED: following into polar equation: x2 +y2 6y = 0 Convert the r= 6cos8 0 ,2 6cos 0 r2 6sin Or = 6sin8
![IF ONE OF THE DIAMETERS OF THE CIRCLE x2+y2-2x-6y+6=0 is a chord to the circle with center (2,1),THEN RADIUS OF - AIEEE - Any Chapter - 800721 | Meritnation.com IF ONE OF THE DIAMETERS OF THE CIRCLE x2+y2-2x-6y+6=0 is a chord to the circle with center (2,1),THEN RADIUS OF - AIEEE - Any Chapter - 800721 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/userimages/mn_images/image/29Mar2011_6.png)
IF ONE OF THE DIAMETERS OF THE CIRCLE x2+y2-2x-6y+6=0 is a chord to the circle with center (2,1),THEN RADIUS OF - AIEEE - Any Chapter - 800721 | Meritnation.com
![algebra precalculus - Understanding how $x^2+2x+y^2-6y-15=0$ becomes $(x+1)^ 2+(y-3)^2=25$ - Mathematics Stack Exchange algebra precalculus - Understanding how $x^2+2x+y^2-6y-15=0$ becomes $(x+1)^ 2+(y-3)^2=25$ - Mathematics Stack Exchange](https://i.stack.imgur.com/WbRqC.jpg)
algebra precalculus - Understanding how $x^2+2x+y^2-6y-15=0$ becomes $(x+1)^ 2+(y-3)^2=25$ - Mathematics Stack Exchange
![Given that a circle has an equation of x^2+y^2+2x-6y-6=0, what is the exact length of AB given that a tangent is drawn from A(6,5) and touches the circle at B? | Socratic Given that a circle has an equation of x^2+y^2+2x-6y-6=0, what is the exact length of AB given that a tangent is drawn from A(6,5) and touches the circle at B? | Socratic](https://useruploads.socratic.org/amAhNsz6SjOLMebCbday_TangentToCircle.png)